Explanation

(d)
$C_{2}H_{5}OH\ and\ {C_{6}H}_{5}OH$ can be distinguished by neutral $FeCl_{3}$ solution or $I_{2}$ +NaOH solution. $C_{2}H_{5}OH$ gives iodoform test with $I_{2} + NaOH$ solution while phenol does not give yellow ppt. of iodoform.
$C_{2}H_{5}OH + 4I_{2} + 6NaOH\overset{\ \ \ \mathrm{\Delta}\ \ \ }{\rightarrow}{CHI}_{3} + HCOONa + 5NaI + 5H_{2}O$
iodoform
$C_{6}H_{5}OH + I_{2} + NaOH \rightarrow$ No reaction
$C_{6}H_{5}OH$ reacts with neutral $FeCl_{3}$solution to give purple colour while $C_{2}H_{5}OH$ doesn’t give any colour with neutral $FeCl_{3}$ solution.