Q. Phenol $\underset{2.CO_{2}/140℃}{\overset{\ \ \ \ \ \ \ 1.NaOH\ \ \ \ \ \ \ }{\rightarrow}}\ A\ \overset{H^{+}/H_{2}O\ }{\rightarrow}\ B\ \overset{\ Ac_{2}O\ \ }{\rightarrow}C$ In this reaction, the end product $C$ is

A) Salicylaldehyde
B) Salicylic acid
C) Phenyl acetate
D) Aspirin
Explanation

The correct answer is Option D: Aspirin.

A detailed explanation for this question is being prepared.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.