Q. Tertiary alkyl halides are practically inert to substitution by $S_{N}2\$mechanism because of
A) Steric hindrance
B) Inductive effect
C) Instability
D) Insolubility
Explanation
(a)
In $S_{N}2$ reaction, nucleophile and alkyl halide react in one step.
[image:10_image58.emf]
Thus, tertiary carbon is under steric hindrance thus reaction does not take place until (C-Br) bond breaks
[image:10_image59.emf]
Which is the $S_{N}1$reaction.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.