Q. Maximum number of molecules of $CH_{3}I$ that can react with a molecule of $CH_{3}NH_{2}\$are
A) 3
B) 4
C) 2
D) 1
Explanation
(a)
$CH_{3}NH_{2}\underset{- HI}{\overset{\ \ \ \ CH_{3}I\ \ \ \ \ }{\rightarrow}}\left( CH_{3} \right)_{2}NH\underset{- HI\ \ }{\overset{CH_{3}I\ \ \ \ }{\rightarrow}}\left( CH_{3} \right)_{3}N\overset{CH_{3}I\ \ }{\rightarrow}\left( CH_{3} \right)_{4}N^{+}I^{-}$
Hence, three molecules of $CH_{3}I$ is used.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.