Q. Of the isomeric hexanes, the isomers that give the minimum and maximum number of monochloro derivatives are respectively

A) 3-methylpentane and 2, 3-dimethylbutane
B) 2, 3-dimethylbutane and n-hexane
C) 2, 2-dimethylbutane and 2-methylpentane
D) 2, 3-dimethylbutane and 2-methypentane
Explanation

(d)
The possible isomers of hexane are
[image:10_image73.emf][image:10_image74.emf]
[image:10_image75.emf][image:10_image76.emf]
Out of these structure (iii) and (i) have respectively minimum and maximum number of monochloro derivatives
For structure(iii)
[image:10_image77.emf] [image:10_image78.emf]
[Only 2 monochloro derivatives (minimum) are possible]
For structure (i).
[image:10_image79.emf][image:10_image80.emf]
[image:10_image81.emf] [image:10_image82.emf]
[image:10_image83.emf]
[5 monochloro derivatives (maximum) are possible]

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.