Q. A bromoalkane ‘X’ reacts with magnesium in dry ether to form compound ‘Y’. The reaction of ‘Y’ with methanal followed by hydrolysis yield an alcohol having molecular formula $C_{4}H_{10}O.$ The compound ‘X’ is
A) Bromoethane
B) Bromomethane
C) 1-bromopropane
D) 2-bromopropane
Explanation
The correct answer is Option C: 1-bromopropane.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.