Q. 1, 2-dibromoethane reacts with alcoholic KOH to yield a product X. The hybridisation state of the carbons present in X respectively, are
A) $sp,\ sp$
B) $sp^{3},\ sp^{3}$
C) $sp^{3},\ sp^{2}$
D) $sp^{3},\ sp^{2}$
Explanation
(a)
Alkyl halides give elimination reaction with alcoholic KOH and yield an alkene or alkyne (from dihalides) $e.g\ .\ ,$
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1,2-dibromo ethane acetylene
Hence, product has both $sp$-hybridised carbon.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.