Q. When tetrahydrafuran is treated with excess HI, the product formed is
A) 1, 4-diiodobutane
B) 1, 4-butanediol
C) 2-iodotetrahydrofuran
D) 4-iodo-1-butanol
Explanation
(a)
Tetrahydrofuran when treated with excess HI, give 1, 4-diiodobutane.
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Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.