Q. Bottles containing $C_{6}H_{5}I\$and $C_{6}H_{5}CH_{2}I\$lost their original labels. They were labelled A and B for testing. A and B were separately taken in a test tube and boiled with NaOH solution. The end solution in each tube was made acidic with dilute $HNO_{3}$ and then some $AgNO_{3}\$solution was added. Substance B gave a yellow precipitate. Which one of the following statements is true for this experiment?

A) A was $C_{6}H_{5}I$
B) A was $C_{6}H_{5}CH_{2}I$
C) B was $C_{6}H_{5}I$
D) Addition of $HNO_{3}$ was unnecessary
Explanation

The correct answer is Option A: A was $C_{6}H_{5}I$.

A detailed explanation for this question is being prepared.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.