Q. Ethyl ester $\underset{(excess)}{\overset{\ \ \ {CH}_{3}MgBr\ \ \ \ }{\rightarrow}}\ P,$ the product ‘P’ will be
A) [image:12_image1.emf]
B) [image:12_image2.emf]
C) [image:12_image3.emf]
D) [image:12_image4.emf]
Explanation
(a)
[image:12_image494.emf]
This ketone is further reacted with excess $CH_{3}MgBr$ (Grignard reagent) and to give $t$-alcohol as the final product. Hence, it is a tertiary butyl alcohol.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.