Q. Collin’s reagent is used to convert
A) [image:12_image38.emf]
B) $- CH_{2}OH \rightarrow - CHO$
C) $- CHO \rightarrow \ - COOH$
D) $- CHO\ \rightarrow \ - CH_{2}OH$
Explanation
The correct answer is Option B: $- CH_{2}OH \rightarrow - CHO$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.