Q. Trichloroacetaldehyde was subjected to Cannizaro’s reaction by using $NaOH$.The mixture of the products contains sodium trichloroacetate ion and another compound. The other compound is
A) 2, 2, 2-trichlorethanol
B) Trichloromethanol
C) 2, 2, 2-trichloropropanol
D) Chloroform
Explanation
(a)
Cannizaro’s reaction is given by aldehydes ($RCHO$) lacking H at $\alpha$-carbon or lacking $\alpha$-carbon (as in $HCHO$). With NaOH, there is formation of acid salt ($RCOO^{-}$) by oxidation and alcohol ($RCH_{2}OH$) by reduction.
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Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.