Q. Salicylic acid is treated with bromine under two different conditions.

Predict the nature of $\lbrack X\rbrack$ and $\lbrack Y\rbrack$ in the above reactions,

A) [image:12_image96.emf]
B) [image:12_image97.emf]
C) [image:12_image98.emf]
D) [image:12_image99.emf]
Explanation

(b)
When some activating group, $eg,\ - OH$ is present along with $–COOH$ is $ortho$ or $para$ position, substitution occurs with respect to $–OH$ preferably at $para$-position due to steric factors. In case the reagent used is strong, electrophile enters at all possible positions even with the replacement of $–COOH$ group

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.