Q. End product of the following reaction is $CH_{3}CH_{2}COOH\underset{red\ P}{\overset{{\ \ \ \ \ Cl}_{2}\ \ \ \ }{\rightarrow}}X\overset{\ \ \ \ Alc.\ KOH\ \ \ }{\rightarrow}$
A) $CH_{3}CH_{2}COOH$
|
$OH$
B) $CH_{2}CH_{2}COOH$
|
OH
C) $CH_{2} = CHCOOH$
D) $CH_{2}CHCOOH$
| |
$Cl\ \ \ \ \ OH$
Explanation
(c)
$CH_{3}CH_{2}COOH\underset{\begin{array}{r}
red\ P \\
(HVZ\ reaction)
\end{array}}{\overset{{\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Cl}_{2}\ \ \ \ \ \ \ \ \ }{\rightarrow}}CH_{3}CHCOOH$
$\ \ \ \ \ \ \ \ \ \ \ \ \ |$
$\ \ \ \ \ \ \ \ \ \ \ \ Cl$
$\underset{(\mathbf{elimination})}{\overset{alcoholic\ KOH}{\rightarrow}}CH_{2} = CHCOOH$
acrylic acid
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.