Q. Cinnamic acid is formed when $C_{6}H_{5} - CHO$ condenses with ($CH_{3}C{O)}_{2}O$ in presence of
A) Concentrated $H_{2}SO_{4}$
B) Sodium acetate
C) Sodium metal
D) Anhydrous $ZnCl_{2}$
Explanation
(b)
When $C_{6}H_{5}CHO$ condenses with $\left( CH_{3}CO \right)_{2}O$ in presence of sodium acetate then cinnamic acid is formed. This reaction is called Perkin reaction.
$C_{6}H_{5} - CHO + \left( CH_{3}CO \right)_{2}O\underset{100℃}{\overset{{CH}_{3}COONa\ \ \ \ \ }{\rightarrow}}C_{6}H_{5}CH = CHCOOH + CH_{3}COOH$
benzaldehyde acetic cinnamic acid
anhydride
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.