Q. In a set of the given reactions, acetic acid yielded a product C. $CH_{3}COOH + PCl_{5} \rightarrow A$ $\ \ \ \ \ \ \ A\underset{arth.\ AlCl_{3}}{\overset{{\ \ \ \ \ \ \ \ \ \ C}_{6}H_{5}\ \ \ \ \ \ \ }{\rightarrow}}B\underset{ether}{\overset{{\ \ C}_{2}H_{5}MgBr\ \ \ }{\rightarrow}}C$ Product C would be
A) $CH_{3}CH(OH)C_{6}H_{5}$
B) ${\ \ \ \ \ \ \ \ \ \ \ \ \ \ C}_{2}H_{5}$
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$CH_{3} - C(OH)C_{6}H_{5}$
C) $CH_{3}CH(OH)C_{2}H_{5}$
D) $CH_{3}COC_{6}H_{5}$
Explanation
(b)
$CH_{3}COOH + PCl_{5} \rightarrow CH_{3}COCl$
(A)
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Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.