Q. Which of the product is formed when acetone is reacted with barium hydroxide solution?
A) $\ \ \ \ \ \ \ \ \ \ \ \ \ \ O\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ CH_{3}$
$\parallel$ |
$CH_{3} - C - CH_{2} - C - CH_{3}$
|
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ OH$
B) $\ \ \ \ \ \ \ \ \ \ \ \ \ \ O$
||
$CH_{3} - C - CH - CH - CH_{3}$
| |
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ CH_{3}\ \ \ OH$
C) O
||
$CH_{3} - C - CH - CH - CH_{3}$
| |
$OH\ \ \ \ \ \ \ \ \ \ \ \ \ \ CH_{3}$
D) $\ \ \ \ \ \ \ \ \ \ \ \ \ OH\ \ \ OH$
| |
$CH_{3} - C - C - CH_{3}$
| |
$\ \ \ \ \ \ \ \ \ \ \ \ \ CH_{3\ }CH_{3}$
Explanation
(a)
When treated with $Ba(OH)_{2},$acetone undergoes aldol condensation to form diacetone alcohol.
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Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.