Q. 2-bromopropanoic acid when heated with alcoholic $KCN$ gives an organic compound which on further acid hydrolysis gives the compound$A$. Hence, $A$ will be:
A) [image:12_image145.emf]
B) $CH_{3}CH(COOH)_{2}$
C) [image:12_image146.emf]
D) [image:12_image147.emf]
Explanation
The correct answer is Option B: $CH_{3}CH(COOH)_{2}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.