(d)
$CH_{3}COOH\ \overset{NH_{3}}{\rightarrow}{CH}_{3}{COONH}_{4}\ \underset{- H_{2}O}{\overset{\ \ \ \ \mathrm{\Delta}\ \ \ }{\rightarrow}}\ CH_{3}CONH_{2}$
acetic acid ammonium acetate acetamide
The isomers of $CH_{3}CONH_{2}$ is
$NH_{2}CH_{2}CHO$
$CH_{3} - CH = NOH$
$H - CONH - CH_{3}$