Q. An ester $(A)C_{11}H_{14}O_{2}$ was treated with $LiAlH_{4}$ to give compound $(B)C_{9}H_{12}O$ and $(C)C_{2}H_{6}O.B$ on slight heating with an acid forms$(D)C_{9}H_{10}$. Compound $D$ on vigorous oxidation with $KMnO_{4}$ gives terephthalic acid. The compound $(A)$, is

A) [image:12_image152.emf]
B) [image:12_image153.emf]
C) [image:12_image154.emf]
D) [image:12_image155.emf]
Explanation

The correct answer is Option A: [image:12_image152.emf].

A detailed explanation for this question is being prepared.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.