Q. With the help of following Grignard synthesis which carboxylic acid is formed? $CH_{2} = CHCH_{2}Br\overset{\ \ Mg/Ether\ \ }{\rightarrow}\underset{(ii)\ H_{3}O^{+}}{\overset{\ \ (i)\ {CO}_{2}\ \ \ }{\rightarrow}}\ ?$
A) $CH_{2} = CHCH_{2}COOH$
B) $CH_{3}CH_{2}CH_{2}COOH$
C) $CH_{2} = CHCOOH$
D) $CH_{3}CH = CH - COOH$
Explanation
The correct answer is Option A: $CH_{2} = CHCH_{2}COOH$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.