Q. Acetyl bromide reacts with excess of $CH_{3}MgI$ followed by treatment with a saturated solution of $NH_{4}Cl$ gives
A) Acetone
B) Acetamide
C) 2-methyl-2-propanol
D) Acetyl iodide
Explanation
The correct answer is Option C: 2-methyl-2-propanol.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.