Phthalic acid $\mathrm{\Delta} \downarrow$ $A\ \overset{NH_{3}}{\rightarrow}\ B\underset{H_{2}O}{\overset{NaOH}{\rightarrow}}\ C\overset{Br_{2}/KOH}{\rightarrow}\ D\ \overset{HCl}{\rightarrow}\ E$ In this reaction, the product $E$ is

Question

Dr. Abubacker · Accepted Answer

The correct answer is Option C: Anthranilic acid.

Q. Phthalic acid $\mathrm{\Delta} \downarrow$ $A\ \overset{NH_{3}}{\rightarrow}\ B\underset{H_{2}O}{\overset{NaOH}{\rightarrow}}\ C\overset{Br_{2}/KOH}{\rightarrow}\ D\ \overset{HCl}{\rightarrow}\ E$ In this reaction, the product $E$ is

Explanation

Reviewed by Dr. Abubacker

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