Q. When benzaldehyde reacts with acetophenone in presence of sodium hydroxide, then product is
A) $C_{6}H_{5}CH = CHCOC_{6}H_{5}$
B) $C_{6}H_{5}COCH_{2}C_{6}H_{5}$
C) $C_{6}H_{5}CH = CHC_{6}H_{5}$
D) $C_{6}H_{5}CH(OH)COC_{6}H_{5}$
Explanation
(a)
In presence of sodium hydroxide, benzaldehyde reacts with acetophenone, to give phenyl cinnamate.
$C_{6}H_{5}CHO + CH_{3}COC_{6}H_{5}\overset{NaOH(aq)\ \ }{\rightarrow}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ O$
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$C_{6}H_{5}CH = CH - C - C_{6}H_{5}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.