Q. Which of the following on heating with aqueous KOH, produces acetaldehyde?
A) $CH_{3}COCl$
B) $CH_{3}CH_{2}Cl$
C) $CH_{2}ClCH_{2}Cl$
D) $CH_{3}CHCl_{2}$
Explanation
(d)
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ O$ O
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$CH_{3} - C - Cl\overset{\ \ \ KOH\ \ \ \ \ }{\rightarrow}CH_{3} - C - O^{-}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ CH_{3}CH_{2}Cl \longrightarrow CH_{3}CH_{2}OH$
$\ \ \ ClCH_{2} - CH_{2}Cl\ \longrightarrow HOCH_{2} - CH_{2}OH$
$\ \ \ \ \ \ \ \ \ \ \ \ \ CH_{3}CHCl_{2} \longrightarrow CH_{3} - CH(OH)_{2}$
Intermediate
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \longrightarrow CH_{3} - CH = O$
Acetaldehyde
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.