Q. Which of the following statements is correct about a carbonyl group?

A) The carbonyl carbon is $sp$-hybridised
B) The carbonyl carbon is $sp^{3}$-hybridised
C) The three groups attached to the carbonyl carbon lie in the same plane
D) The three groups attached to the carbonyl carbon lie in different planes
Explanation

(c)
In the carbonyl group, carbon atom is in a state of $sp^{2}$ hybridisation. One $sp^{2}$ hybrid orbital overlap with a unhydridised $p$-orbital of oxygen to form $C - O$ $\sigma$-bonds. The remaining two $sp^{2}$ orbitals of carbon from $\sigma$-bonds with $s$-orbitals of hydrogen or $sp^{3}$-orbitals of carbon of the alkyl groups. The $C - O$ $\pi$-bond is formed by the sideways overlap of $p$-orbitals of carbon and oxygen. Thus, the three $\sigma$-bonds of carbonyl carbon lie in one plane and are $120{^\circ}$ aprat
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Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.