Q. When $CH_{2} = CH - COOH$ is reduced with $LiAlH_{4}$, the compound obtained will be
A) $CH_{3} - CH_{2} - COOH$
B) $CH_{2} = CH - CH_{2}OH$
C) $CH_{3}CH_{2}CH_{2}OH$
D) $CH_{3}{CH}_{2}CHO$
Explanation
(b)
$LiAlH_{4}$ reduces $–COOH$ group to $–CH_{2}OH$ group without affecting C=C bond.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.