Q. $CH_{3}COOH\overset{\ \ \ \ LiAlH_{4}\ \ \ }{\rightarrow}\ X\underset{300^{0}C}{\overset{\ \ \ \ \ Cu\ \ \ \ \ \ }{\rightarrow}}Y\underset{NaOH}{\overset{\ \ \ \ \ Dilute\ \ \ \ }{\rightarrow}}Z.$ In the above reaction $Z$ is

A) Butanol
B) Aldol
C) Ketol
D) Acetal
Explanation

The correct answer is Option B: Aldol.

A detailed explanation for this question is being prepared.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.