Q. The enol form of acetone after treatment with $D_{2}O$, give
A) $H_{3} - C = CH_{3}$
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$OD$
B) $H_{3}C - C - CD_{3}$
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$O$
C) $H_{2}C = C - CH_{2}D$
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$OH$
D) $H_{2}C = C - CHD_{2}$
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$OH$
Explanation
The correct answer is Option A: $H_{3} - C = CH_{3}$ | $OD$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.