Q. Sodium ethoxide has reacted with ethanoyl chloride. The compound that is produced in the above reaction is
A) Diethyl ether
B) 2-butanone
C) Ethyl chloride
D) Ethyl ethanoate
Explanation
(d)
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This is by $S_{N}$ reaction. $Cl^{-}$ is a better leaving group than $C_{2}H_{5}O^{-}$ and the ethyl ethanoate is formed.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.