Q. Which of the following carboxylic acids is not reduced to the corresponding $1{^\circ}$ alcohol by$LiAlH_{4}$ ?
A) $BrCH_{2}CH_{2}CH_{2}COOH$
B) Cyclohexane carboxylic acid
C) $(Z) - CH_{3}CH = CHCH_{2}COOH$
D) $CH_{3}CH\left( CH_{3} \right)CH_{2}COOH$
Explanation
(a)
$LiAlH_{4}$ is a strong reducing agent, which reduces carboxylic acids to corresponding primary alcohols as well as alkyl halide to alkenes, but donot reduce double bond
$BrCH_{2}CH_{2}CH_{2}COOH\ \overset{LiAlH_{4}}{\rightarrow}\ CH_{3}CH_{2}CH_{2}{CH}_{2}OH$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.