(b)
$CH_{3}CHO + HCH_{2}COCH_{3}\overset{\ \ NaOH\ \ \ \ \ }{\rightarrow}$
$CH_{3}CH(OH)CH_{2}COCH_{3} + CH_{3}CH(OH)CH_{2}CHO$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \$major
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ + \left( CH_{3} \right)_{2}C(OH)CH_{2}COCH_{3}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ + \left( CH_{3} \right)_{2}C(OH) - CH_{2}CHO$
$CH_{3}CH(OH)CH_{2}COCH_{3}\underset{{- H}_{2}O}{\overset{\ \ \ \ \ \ \ \mathrm{\Delta}\ \ \ \ \ \ \ }{\rightarrow}}CH_{3}CH = CHCOCH_{3}$
major product major product(25%)