Q. Aldehydes and ketones can be reduced to hydrocarbon by using

A) $LiAlH_{4}$
B) $\frac{H_{2}}{Pd\ } - BaSO_{4}$
C) Na-Hg /HCl
D) ${NH}_{2}\ –{NH}_{2}/C_{2}H_{5}ONa$
Explanation

(d)
By$\ NH_{2} - NH_{2}/C_{2}H_{5}ONa$
Aldehyde and ketones are reduced with hydrazine $NH_{2} - NH_{2}$ and $C_{2}H_{5}ONa$ to give hydrocarbon (paraffins). This reaction is called Wolff-Kishner reaction.
$- CHO\underset{C_{2}H_{5}ONa}{\overset{{\ \ \ \ \ NH}_{2} - NH_{2}\ \ \ }{\rightarrow}} - CH_{3} - CO - \underset{C_{2}H_{5}ONa}{\overset{{NH}_{2} - NH_{2}}{\rightarrow}} - CH_{2} -$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.