Q. In the Rosenmund’s reaction $RCOCl + H_{2}\overset{\ \ \ Pd/BaSO_{4}\ \ }{\rightarrow}\ RCHO + HCl$ $BaSO_{4}$ here
A) Promotes catalytic activity of Pd
B) Removes the $HCl$ formed in the reaction
C) Deactivates palladium
D) Activates palladium
Explanation
(c)
In the Rosenmund’s reaction, acid chlorides are converted to corresponding aldehydes by catalytic reduction. The reaction is carried out by passing through a hot solution of the acid chloride in the presence of Pd deposited over $BaSO_{4}$.Here, barium sulphate decrease the activity of palladium
$RCOCl + H_{2}\overset{\ \ \ Pd/BaSO_{4\ \ }\ }{\rightarrow}RCHO + HCl$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.