Q. Identify A and B in the following reaction $CH_{3} - CH_{3}\overset{\ \ \ \ B\ \ \ }{\leftarrow}CH_{3}COOH\overset{\ \ \ A\ \ \ \ \ }{\rightarrow}CH_{3}CH_{2}OH$ A B
A) $HI + red\ P$ $LiAlH_{4}$
B) $Ni/\mathrm{\Delta}$ $LiAlH_{4}$
C) $LiAlH_{4}$ $HI + red\ P$
D) $Pd - BaSO_{4}$ $\ Zn + HCl$
Explanation
(c)
Acetic acid on reduction with lithium aluminiumhydride ($LiAlH_{4}$) gives ethyl alcohol while on reduction with HI and red P gives ethane.
$CH_{3}COOH\overset{LiAlH_{4}\ \ \ \ }{\rightarrow}CH_{3}CH_{2}OH$
ethyl alcohol
$CH_{3}COOH\overset{Red\ P\ + HI}{\rightarrow}CH_{3} - CH_{3}$
Ethane
Hence, reagent A and B are respectively $LiAlH_{4}$ and HI/red P.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.