$CH_{3}CH_{2}OH\ \underset{I}{\overset{Cu,\ 573\ K}{\rightarrow}}\ X\underset{II}{\overset{\lbrack O\rbrack}{\rightarrow}}\ Y\ \underset{III}{\overset{{Br}_{2},P}{\rightarrow}}\ BrCH_{2}COOH$ Reaction I, II and III respectively are

Question

Dr. Abubacker · Accepted Answer

The correct answer is Option C: Dehydrogenation, oxidation and substitution.

Q. $CH_{3}CH_{2}OH\ \underset{I}{\overset{Cu,\ 573\ K}{\rightarrow}}\ X\underset{II}{\overset{\lbrack O\rbrack}{\rightarrow}}\ Y\ \underset{III}{\overset{{Br}_{2},P}{\rightarrow}}\ BrCH_{2}COOH$ Reaction I, II and III respectively are

Explanation

Reviewed by Dr. Abubacker

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