Q. $CH_{3}CHO + HCHO\ \underset{Heat}{\overset{\ \ \ Dil.NaOH\ \ \ \ }{\rightarrow}}A\ \ \ \underset{H_{3}O^{+}}{\overset{\ \ \ \ HCN\ \ \ \ \ }{\rightarrow}}B\$. The structure of compound $B$ is
A) $CH_{2} = CH - CH - COOH$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ OH$
B) $CH_{2} = CH - CH - OH$
|
$CN$
C) $CH_{3}CH_{2} - CH - COOH$
|
$OH$
D) $CH_{3} - CH - COOH$
|
$OH$
Explanation
The correct answer is Option A: $CH_{2} = CH - CH - COOH$ $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |$ $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ OH$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.