Q. The compound that will react most readily with $NaOH\$to form methanol is
A) $\left( CH_{3} \right)_{4}N^{+}I^{-}$
B) $CH_{3}OCH_{3}$
C) $\left( CH_{3} \right)S^{+}I^{-}$
D) $\left( CH_{3} \right)_{3}CCl$
Explanation
The correct answer is Option A: $\left( CH_{3} \right)_{4}N^{+}I^{-}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.