Q. $A\overset{H_{2}NOH\ }{\rightarrow}B{\overset{Reduction\ }{\rightarrow}C{\overset{NOCl\ }{\rightarrow}CH_{3}CH_{2}Cl}}$ In the above sequence $A\$and $C\$are
A) Methanal, methyl amine
B) Acetone, ethaneamine
C) Ethanal, diamethyl amine
D) Acetaldehyde, ethyl amine
Explanation
(d)
${CH}_{3}CHO\overset{H_{2}NOH}{\rightarrow}{CH}_{3}CH = NOH{\overset{Reduction}{\rightarrow}{CH}_{3}{CH}_{2}{NH}_{2}{\underset{\begin{array}{r}
- N_{2} \\
- H_{2}O
\end{array}}{\overset{NOCl}{\rightarrow}}CH_{3}CH_{2}Cl}}$
Acetaldehyde ethyl amine ethyl chloride
$\ \ \ (A)\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (B)\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (C)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.