Q. Decreasing order of basicity of the three isomers of methoxyaniline is
A) $p$-$CH_{3}OC_{6}H_{4}NH_{2} > o - CH_{3}OC_{6}H_{4}NH_{2} > m - CH_{3}OC_{6}H_{4}NH_{2}$
B) $p$-$CH_{3}OC_{6}H_{4}NH_{2} > m - CH_{3}OC_{6}H_{4}NH_{2} > o - CH_{3}OC_{6}H_{4}NH_{2}$
C) $o$-$CH_{3}OC_{6}H_{4}NH_{2} > p - CH_{3}OC_{6}H_{4}NH_{2} > m - CH_{3}OC_{6}H_{4}NH_{2}$
D) $o$-$CH_{3}OC_{6}H_{4}NH_{2} > m - CH_{3}OC_{6}H_{4}NH_{2} > p - CH_{3}OC_{6}H_{4}NH_{2}$
Explanation
The correct answer is Option C: $o$-$CH_{3}OC_{6}H_{4}NH_{2} > p - CH_{3}OC_{6}H_{4}NH_{2} > m - CH_{3}OC_{6}H_{4}NH_{2}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.