Q.
In the following reaction,$X\overset{Bromination}{\rightarrow}Y\underset{+ HCI}{\overset{{NaNO}_{2}}{\rightarrow}}Z\underset{C_{2}H_{5}OH}{\overset{Boiling}{\rightarrow}}$ tribromo benzene. X is
A) Benzoic acid
B) Salicylic acid
C) Phenol
D) Aniline
Explanation
The correct answer is Option D: Aniline.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.