Explanation

(d)
$HNO_{2}$ reacts to give an alcohol means the compound is primary amine.
$C_{5}H_{13}N$ means $C_{5}H_{11}NH_{2}$(primary amine)
Optically active alcohol means $C_{5}H_{11}$ segment contain a chiral carbon.
$H$
5 4 3 2 $|$
$CH_{3} - CH_{2} - CH_{2} - C - NH_{2}$
$|$
1 $CH_{3}$
Pentan-2-amine