Q. Amongst the compound given, the one that would form a brilliant coloured dye on treatment with $NaNO_{2}$ in dil. $HCI$ followed by addition to an alkaline solution of $\beta -$naphthol is
A) [image:13_image76.emf]
B) [image:13_image77.emf]
C) [image:13_image78.emf]
D) [image:13_image79.emf]
Explanation
(c)
As we know, benzenediazonium salt forms brilliant coloured dye with $\beta$-naphthol, the compound under consideration must be p-toludine (c) as it is a primary aromatic amine. Primary aromatic amine, on treatment with $NaNO_{2}$ in dil. HCI forms the corresponding diazonium chloride salt.
[image:13_image203.emf]
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.