Q. An organic compound ‘A ’ having molecular formula $C_{2}H_{3}N$ on reduction gave another compound B, upon treatment with nitrous acid ‘B ’ gave ethyl alcohol. On warming with chloroform and alcoholic KOH, it formed an offensive smelling compound ‘C ’. The compound ‘C ’ is
A) $CH_{3}CH_{2}NH_{2}$
B) [image:13_image88.emf]
C) $CH_{3}C \equiv N$
D) $CH_{3}CH_{2}.OH$
Explanation
(b)
$CH_{3} - C \equiv N\overset{Reduction}{\rightarrow}CH_{3}CH_{2}NH_{2}\overset{HONO}{\rightarrow}CH_{3}CH_{2}OH$
methyl cyanide ethanamine ethanol
(B)
$CH_{3}CH_{2}NH_{2}\overset{CHCI_{3},KOH}{\rightarrow}CH_{3}CH_{2}N\overrightarrow{=}C$
Ethyl isocyanide
(C)
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.