Q. Given the following sequence of reactions, $CH_{3}CH_{2}I\overset{NaCN}{\rightarrow}A\underset{\begin{array}{r} Partial \\ hydrolysis \end{array}}{\overset{{OH}^{-}}{\rightarrow}}B\overset{Br_{2}/NaOH}{\rightarrow}C$ The major product ‘C ‘ is
A) $CH_{3}CH_{2}NH_{2}$
B) $CH_{3}.CH_{2}C - NHBr$
$||$
$\ O$
C) $CH_{3}.CH_{2} - COONH_{4}$
D) $CH_{3}.CH_{2}C - {NBr}_{2}$
$||$
$\ O$
Explanation
(a)
$CH_{3}CH_{2}I\overset{NaCN}{\rightarrow}CH_{3}CH_{2}CN\overset{OH^{-}}{\rightarrow}CH_{3}CH_{2}CONH_{2}\overset{Br_{2}/NaOH}{\rightarrow}CH_{3}CH_{2}NH_{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.