Q. The end product in the below reaction is $C_{2}H_{5}NH_{2}\overset{HNO_{2}}{\rightarrow}\ A{\overset{PCl_{5}}{\rightarrow}\ B{\overset{NH_{3}}{\rightarrow}\ C}}$

A) Ethyl cynide
B) Ethyl amine
C) Methyl amine
D) Acetamide
Explanation

(b)
$C_{2}H_{5}NH_{2}\overset{\ \ \ HNO_{2\ \ \ \ }}{\rightarrow}C_{2}H_{5}OH{\overset{\ \ \ {PCl}_{5}\ \ }{\rightarrow}C_{2}H_{5}Cl{\overset{\ \ \ \ \ NH_{3\ \ \ \ \ \ \ \ }}{\rightarrow}{\ C}_{2}H_{5}{NH}_{2}}}$
Ethyl amine ethyl alcohol ethyl chloride ethyl amine
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (A)\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (B)\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (C)$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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