Q. Increasing order of basicity of $CH_{3}CH_{2}CH_{2}NH_{2}$ $H_{2}C = CHCH_{2}NH_{2}\ and\ HC \equiv CCH_{2}NH_{2}$ is
A) $CH_{3}CH_{2}CH_{2}NH_{2}$< $HC \equiv CCH_{2}NH_{2} < H_{2}C = CHCH_{2}{NH}_{2}$
B) $CH_{3}CH_{2}CH_{2}NH_{2} < H_{2}C = CHCH_{2}NH_{2} < CH \equiv CCH_{2}NH_{2}$
C) $HC \equiv CCH_{2}NH_{2} < H_{2}C = CHCH_{2}NH_{2} < CH_{3}CH_{2}CH_{2}NH_{2}$
D) $CH \equiv CCH_{2}NH_{2} < CH_{3}CH_{2}CH_{2}NH_{2} < H_{2}C = CHCH_{2}NH_{2}$
Explanation
(c)
Electron deficient group decreases the electron density of N-atom, thus, makes its lone pair less available for donation
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.