Q. Isopropyl amine with excess of acetyl chloride will give
A) $\left( CH_{3}CO \right)_{2}N - CH - \left( CH_{3} \right)_{2}$
B) $\left( CH_{3} \right)_{2}CH - N - COCH_{3}$
$|$
$H$
C) $\left( CH_{3} \right)_{2}CHN\left( COCH_{3} \right)_{2}$
D) $CH_{3}CH_{2}CH_{2} - N - COCH_{3}$
$|$
$H$
Explanation
(c)
$\left( CH_{3} \right)_{2}CH.NH_{2} + 2CH_{3}COCI\overset{\rightarrow}{- HCI}\left( CH_{3} \right)_{2}CH - N\left( COCH_{3} \right)_{2}$
iso-propyl amine (ter-amine)
(pri amine)
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.