Q. The compound will react most readily with $NaOH$ to form methanol is
A) $\left( CH_{3} \right)_{4}N^{+}I^{-}$
B) $CH_{3}OCH_{3}$
C) $\left( CH_{3} \right)_{3}S^{+}I^{-}$
D) $\left( CH_{3} \right)_{3}CI$
Explanation
(a)
$\left( CH_{3} \right)_{4}N^{+}I^{-} + NaOH \rightarrow \left( CH_{3} \right)_{4}N^{+}OH^{-} + Nal$
$\left( CH_{3} \right)_{4}N^{+}OH^{-}\overset{\mathrm{\Delta}}{\rightarrow}\left( CH_{3} \right)_{3}N + CH_{3}OH$
methanol
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.