Q. $C_{6}H_{5}NO_{2}\overset{Sn/HCl}{\rightarrow}C_{6}H_{5}X$ ‘X ’ is identified as

A) NO
B) $- NH_{2}$
C) NHOH
D) None of these
Explanation

(b)
$C_{6}H_{5}NO_{2}\underset{\lbrack H\rbrack}{\overset{Sn/HCl}{\rightarrow}}C_{6}H_{5}NH_{2}$
Nitrobenzene Aniline
Nitrobenzene in reduction with Sn and HCI produce aniline. Hence, ‘X ’ is identified as $–NH_{2}$ group.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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